If you want to know how to generate a Random Int number using C#, then you have come to the right place.C# is one of the main .NET languages and is used to build Windows apps. We will use it to generate Random Int numbers.
To generate a Random Int Number using C#, you need to use the following code.
Random randm = new Random(): int rand_month = randm.Next(1,13); int rand_dice = randm.Next(1,7); int rand_card_value = randm.Next(52);
How To Generate a Random Int Number
As you can see from the above code, the Next() function is used to generate a random number. The only downside is that you need to input both a starting and ending value. However, it should always be kept in mind that the minValue(starting value) is inclusive, whereas maxValue(ending value) is exclusive.
Next(minValue, MaxValue)
The biggest mistake that learners make with the Next() function is to think that the random value is generated in between the min and max values. However, that’s not the case. So, if you want to randomly generate the month for your app (int rand_month in the example), you need to set minValue to 1 and maxValue to 13. You can read more about here.
Another aspect that you need to understand is that the random value generation depends on the system clock. So, if you run two random generators at the same time, they will generate the same value rather than two different values. To overcome the problem, you need to store the first random value and then generate another random value.
Another caveat that you need know is that you won’t be able to generate 32 or 64-bit random bits. For generating 32 or 64-bit random bits, you need to use the NextInt32() or NextInt64() extension methods from Medallion Random.
If you have any questions regarding Random Int number generation in C#, then comment below and let us know.
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Also Check Learn C# – How To Get a Consistent Byte Representation of Strings?
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I think no other explanation could have better than this. thanks